JEE Main 24 June 2022 Shift 2 Solved Paper

Section: Mathematics

Question : 29 of 90

Marks: +1, -0

Let the hyperbola H:‌

−y2=1 and the ellipse E:3x2+4y2=12 be such that the length of latus rectum of H is equal to the length of latus rectum of E. If eH and eE are the eccentricities of H and E respectively, then the value of 12(eH2+eE2) is equal to

[24-Jun-2022-Shift-2]

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