JEE Main 24 June 2022 Shift 2 Solved Paper

Section: Mathematics

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Question : 17 of 90

Marks: +1, -0

If y=tan−1(sec‌x3−tan‌x3),‌

π

2

<x3<‌

3π

2

, then

[24-Jun-2022-Shift-2]

xy′′+2y′=0
x2y′′−6y+‌
3π
2
=0
x2y′′−6y+3π=0
xy′′−4y′=0

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