JEE Main 24 June 2022 Shift 1 Solved Paper

C15H30+‌

45

2

O2→15CO2+15H2O
Given, volume of fuel =1L=1000ml
And density of fuel =0.756g∕ml
We know,
d=‌

w

v

⇒0.756=‌

w

1000

⇒W=756gm
∴ weight of fuel =756gm
Molar mass of C15H30=15×12+30=210
∴ Moles of C15H30=‌

756

210

From equation you can see,

1 mole of C15H30 react with ‌

45

2

mole of O2
∴‌

756

210

moles of C15H30 react with ‌

45

2

×‌

756

210

moles of O2
∴ Moles of O2 required =‌

45

2

×‌

756

210

∴ Mass of O2 required =‌

45

2

×‌

756

210

×32= 2592g
Also,
From 1 mole of C15H3015 moles of CO2 formed
∴ From ‌

756

210

moles of C15H3015×‌

756

210

moles of CO2 formed
∴ Moles of CO2 formed =15×‌

756

210

∴ Mass of CO2 formed =15×‌

756

210

×44=
2376g