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JEE Main 24 June 2022 Shift 1 Solved Paper

Section: Mathematics
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Question : 27 of 90
 
Marks: +1, -0
Let
Max
0≤x≤2
{‌
9−x2
5−x
}=α and
Min
0≤x≤2
{‌
9−x2
5−x
}=β.
If
2α−1
∫
β−‌
8
3
Max{‌
9−x2
5−x
,x}‌d‌x=α1+α2loge(‌
8
15
) then α1+α2 is equal to
[24-Jun-2022-Shift-1]
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