JEE Main 24 June 2022 Shift 1 Solved Paper

Section: Mathematics

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Question : 14 of 90

Marks: +1, -0

If x=x(y) is the solution of the differential equation
y‌

dx

dy

=2x+y3(y+1)ey,x(1)=0; then x(e) is equal to:

[24-Jun-2022-Shift-1]

e3(ee−1)
ee(e3−1)
e2(ee+1)
ee(e2−1)

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