JEE Main 24 Jan 2026 Shift 1 Paper Solved Paper

Section: Mathematics

Question : 3 of 75

Marks: +1, -0

Let A1 be the bounded area enclosed by the curves y=x2+2,x+y=8 and y-axis that lies in the first quadrant. Let A2 be the bounded area enclosed by the curves y=x2+2,y2=x,x=2, and y-axis that lies in the first quadrant. Then A1−A2 is equal to

[24 jan 2026 Shift 1]

‌
2
3
(2√2+1)
‌
2
3
(3√2+1)
‌
2
3
(√2+1)
‌
2
3
(4√2+1)

Validate

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