JEE Main 24 Jan 2025 Shift 2 Paper
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Question : 13 of 75
Marks:
+1,
-0
Let
A = { x ∈ ( 0 , π ) − (
) : log ( 2 ∕ π ) | s i n x | + log ( 2 ∕ π ) | cos x | = 2 }
andB = { x ≥ 0 : √ x ( √ x − 4 ) − 3 | √ x − 2 | + 6 = 0 } . Then n ( A ∪ B ) is equal to
and
[24 Jan 2025 Shift 2]
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