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Question : 7 of 75
Marks:
+1,
-0
Solution:
‌=+2+3‌=3+−‌‌ and ‌=k(+λ)‌ (for some scalar ‌λ)‌∴‌‌=k((1+3λ)+(2+λ)+(3−λ))‌∵⋅=0‌3(1+3λ)+(2+λ)−(3−λ)=0‌∴‌‌λ=‌‌∴‌‌=k(‌+‌+‌)‌∵‌‌⋅=5⇒k=‌‌∴‌‌=‌(5+20+35)‌‌‌=‌(+4+7)‌∴‌‌||=√‌
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