An electron of mass ' m ' with an initial velocity \overrightarrow{v}=v_0 \stackrel{\^}{i} (v_0>0) enters an electric field \overrightarrow{E}=-E_0 \stackrel{\^}{k}. If the initial de Broglie wavelength is \lambda_0, the value after t would be [24 Jan 2025 Shift 1]

Correct Answer is : λ0√1+e2E02t2m2v02

{\lambda_0}/\sqrt{1+\frac{e^2 E_0^2 t^2}{m^2 v_0^2}}}

\lambda_0 \sqrt{1+\frac{e^2 E_0^2 t^2}{m^2 v_0^2}}

{\lambda_0}/\sqrt{1- {e^2 E_0{ }^2 t^2}/{m^2 v_0{ }^2}}}

JEE Main 24 Jan 2025 Shift 1 Paper

Section: Physics

Question : 45 of 75

Marks: +1, -0

An electron of mass ' m ' with an initial velocity

→

=v0

(v0>0) enters an electric field

→

=−E0

. If the initial de Broglie wavelength is λ0, the value after t would be

[24 Jan 2025 Shift 1]

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