JEE Main 24 Jan 2025 Shift 1 Paper

Section: Physics

Question : 41 of 75

Marks: +1, -0

A force F=α+βx2 acts on an object in the x-direction. The work done by the force is 5 J when the object is displaced by 1 m . If the constant α=1N then β will be

[24 Jan 2025 Shift 1]

8N∕m2
15N∕m2
12N∕m2
10N∕m2

Validate

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