Let in a \triangle A B C, the length of the side A C be 6 , the vertex B be (1,2,3) and the vertices A, C lie on the line \frac{x-6}{3}=\frac{y-7}{2}=\frac{z-7}{-2}. Then the area (in sq. units) of \triangle A B C is: [24 Jan 2025 Shift 1]

JEE Main 24 Jan 2025 Shift 1 Paper

Section: Mathematics

Question : 3 of 75

Marks: +1, -0

Let in a △ABC, the length of the side AC be 6 , the vertex B be (1,2,3) and the vertices A,C lie on the line ‌

x−6

=‌

y−7

=‌

z−7

−2

. Then the area (in sq. units) of △ABC is:

[24 Jan 2025 Shift 1]

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