JEE Main 24 Jan 2025 Shift 1 Paper

Section: Mathematics
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Question : 11 of 75
 
Marks: +1, -0
Let y=y(x) be the solution of the differential equation ‌‌(xy−5x2√1+x2)‌dx+(1+x2)dy=0, y(0)=0. Then y(√3) is equal to
[24 Jan 2025 Shift 1]
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