The vector equation of the plane passing through the intersection of the planes r \cdot({i^{∧}+j+{k^{∧})=1 and r \cdot({i^{∧}-2 {j^{∧})=-2 and the point (1,0,2) is [24 Feb 2021 Shift 2]

Correct Answer is : r⋅(∧i+7∧j+3∧k)=7

r \cdot({i^{∧}+7 {j^{∧}+3 {k^{∧})=\frac{7}{3}

r \cdot(3 {i^{∧}+7 {j^{∧}+3 {k^{∧})=7

r \cdot({i^{∧}+7 {j^{∧}+3 {k^{∧})=7

r \cdot({i^{∧}-7 {j^{∧}+3 {k^{∧})=\frac{7}{3}

JEE Main 24 Feb 2021 Shift 2 Solved Paper

Section: Mathematics

Question : 63 of 90

Marks: +1, -0

The vector equation of the plane passing through the intersection of the planes r⋅(

∧

+j+

∧

)=1 and r⋅(

∧

−2

∧

)=−2 and the point (1,0,2) is

[24 Feb 2021 Shift 2]

Go to Question:

Prev Question

Next Question