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JEE Main 24 Feb 2021 Shift 2 Solved Paper

Section: Physics
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Question : 27 of 90
 
Marks: +1, -0
A signal of 0.1kW is transmitted in a cable. The attenuation of cable is −5dB per km and cable length is 20km. The power received at receiver is 10−xW. The value of x is .......... .
[Gain in dB =10log10(‌
P0
Pi
) ]
[24 Feb 2021 Shift 2]
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