JEE Main 24 Feb 2021 Shift 2 Solved Paper

Section: Physics

Question : 19 of 90

Marks: +1, -0

A particle is projected with velocity v0 along x-axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin, i.e. ma=−αx2. The distance at which the particle stops is

[24 Feb 2021 Shift 2]

(‌
3mv02
2α
)‌
1
2
(‌
2mv0
3α
)‌
1
3
(‌
2mv02
3α
)‌
1
2
(‌
3mv02
2α
)‌
1
3

Validate

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