JEE Main 23 Jan 2026 Shift 1 Paper Solved Paper

Section: Mathematics

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Question : 6 of 75

Marks: +1, -0

Let f(x)=∫‌

(2−x2)⋅ex

(√1+x)(1−x)3∕2

‌dx. If f(0)=0, then f(‌

1

2

) is equal to:

[23 Jan 2026 Shift 1]

√2e−1
√2e+1
√3e−1
√3e+1

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