JEE Main 23 Jan 2025 Shift 2 Paper

Section: Mathematics

Question : 5 of 75

Marks: +1, -0

Let the shortest distance from (a,0),a>0, to the parabola y2=4x be 4 . Then the equation of the circle passing through the point (a,0) and the focus of the parabola, and having its centre on the axis of the parabola is

[23 Jan 2025 Shift 2]

x2+y2−6x+5=0
x2+y2−10x+9=0
x2+y2−4x+3=0
x2+y2−8x+7=0

Validate

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