{\CrCl}_{3 .} {\xNH}_3 can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558^{\circ} {\C}. Assuming 100 \% ionisation of this complex and coordination number of Cr is 6 , the complex will be (Given {\K}_{ {\f}}=1.86 {\K} {\kg} {\mol}^{-1} ) [23 Jan 2025 Shift 1]

Correct Answer is : [Cr(NH3)5Cl]Cl2

[ {\Cr} ( {\NH}_3) _4 {\Cl}_2] {\Cl}

[ {\Cr} ( {\NH}_3) _5 {\Cl}] {\Cl}_2

JEE Main 23 Jan 2025 Shift 1 Paper

Section: Chemistry

Question : 62 of 75

Marks: +1, -0

CrCl3.xNH3 can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558∘C. Assuming 100% ionisation of this complex and coordination number of Cr is 6 , the complex will be
(Given Kf=1.86K‌kg‌mol−1 )

[23 Jan 2025 Shift 1]

[Cr(NH3)4‌Cl2]‌Cl
[Cr(NH3)3‌Cl3]
[Cr(NH3)6]Cl3
[Cr(NH3)5‌Cl]Cl2

Validate

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