JEE Main 23 Jan 2025 Shift 1 Paper

Section: Chemistry

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Question : 52 of 75

Marks: +1, -0

FeO42−

+2.0V

───────▶

Fe3+

0.8V

───────▶

Fe2+───────▶−0.5VFe0
In the above diagram, the standard electrode potentials are given in volts (over the arrow). The value of EFeO42−∕Fe2+⊖ is

[23 Jan 2025 Shift 1]

1.7 V
2.1 V
1.4 V
1.2 V

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