JEE Main 23 Jan 2025 Shift 1 Paper

Section: Mathematics

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Question : 20 of 75

Marks: +1, -0

The value of

e4

∫

e2

‌

1

x

(‌

e((logex)2+1)−1

e(logex)2+1)−1+e((6−logex)2+1)−1

)‌dx is

[23 Jan 2025 Shift 1]

1
e2
2
loge2

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