JEE Main 22 July 2021 Shift 2 Solved Paper

Section: Mathematics

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Question : 78 of 90

Marks: +1, -0

Let f:R→R be defined as

f(x)={

x3

(1−cos‌2‌x)2

logc(

1+2xe−2x

(1−xe−x)2

),

x≠0

α,

x=0

If f is continuous at x=0, then alpha is equal to :

[22 Jul 2021 Shift 2]

1
3
0
2

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