Match List-I with List-II : List–I List–II (a) \\omega{L}>{1}/{\\omega{C}} (i) Current is in phase with emf (b) \\omega{L}={1}/{\\omega{C}} (ii) Current lags behind the applied emf (c) \\omega{L} (iii) Maximum current occurs (d) Resonant frequency (iv) Current leads the emf Choose the correct answer from the options given below : [22 Jul 2021 Shift 2]

Correct Answer is : (a) – (ii) ; (b) – (i) ; (c) - (iv) ; (d) – (iii)

(a) – (ii) ; (b) – (i) ; (c) - (iv) ; (d) – (iii)

(a) – (ii) ; (b) – (i) ; (c) - (iii) ; (d) – (iv)

(a) – (iii) ; (b) – (i) ; (c) - (iv) ; (d) – (ii)

(a) – (iv) ; (b) – (iii) ; (c) - (ii) ; (d) – (i)

JEE Main 22 July 2021 Shift 2 Solved Paper

Section: Physics

Question : 14 of 90

Marks: +1, -0

Match List-I with List-II :

List–I

List–II

(a)

ωL>

ωC

(i)

Current is in phase with emf

(b)

ωL=

ωC

(ii)

Current lags behind the applied emf

(c)

ωL<

ωC

(iii)

Maximum current occurs

(d)

Resonant frequency

(iv)

Current leads the emf

Choose the correct answer from the options given below :

[22 Jul 2021 Shift 2]

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