Let S and S ^{'} be the foci of the ellipse \frac{x^2}{25}+\frac{y^2}{9}=1 and P (\alpha, \beta) be a point on the ellipse in the first quadrant. If ( SP )^2+ ( S ^{'} P ) ^2- SP \cdot S ^{'} P =37, then \alpha^2+\beta^2 is equal to: [22 Jan 2026 Shift 2]

JEE Main 22 Jan 2026 Shift 2 Paper Solved Paper

Section: Mathematics

Question : 5 of 75

Marks: +1, -0

Let S and S′ be the foci of the ellipse ‌

+‌

=1 and P(α,β) be a point on the ellipse in the first quadrant. If (SP)2+(S′P)2−SP⋅S′P=37, then α2+β2 is equal to:

[22 Jan 2026 Shift 2]

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