Let the solution curve of the differential equation x d y-y \dx=\sqrt{x^2+y^2} \dx, x>0, y(1)=0, be y=y(x). Then y(3) is equal to [22 Jan 2026 Shift 1]

JEE Main 22 Jan 2026 Shift 1 Paper Solved Paper

Section: Mathematics

Question : 7 of 75

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Let the solution curve of the differential equation xdy−y‌dx=√x2+y2‌dx,x>0,y(1)=0, be y=y(x). Then y(3) is equal to

[22 Jan 2026 Shift 1]

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