JEE Main 22 Jan 2026 Shift 1 Paper Solved Paper

Section: Mathematics

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Question : 16 of 75

Marks: +1, -0

The coefficient of x48 in (1+x)+2(1+x)2+3(1+x)3+...+100(1+x)100 is equal to

[22 Jan 2026 Shift 1]

100⋅‌100C49−‌100C48
100⋅‌101C49−‌101C50
‌100C50+‌101C49
100⋅‌100C49−‌100C50

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