JEE Main 22 Jan 2026 Shift 1 Paper Solved Paper

Section: Mathematics

Question : 13 of 75

Marks: +1, -0

Let f(x)=x2025−x2000,x∈[0,1] and the minimum value of the function f(x) in the interval [0,1] be (80)80(n)−81. Then n is equal to

[22 Jan 2026 Shift 1]

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