JEE Main 22 Jan 2025 Shift 2 Paper
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Question : 4 of 75
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Let α , β , γ and δ be the coefficients of x 7 , x 5 , x 3 and x respectively in the expansion of ( x + √ x 3 − 1 ) 5 + ( x − √ x 3 − 1 ) 5 , x > 1 . If u and v satisfy the equations
α u + β v = 18 ,
γ u + δ v = 20 ,
thenu + v equals:
then
[22 Jan 2025 Shift 2]
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