JEE Main 22 Jan 2025 Shift 2 Paper

Section: Mathematics
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Question : 25 of 75
 
Marks: +1, -0
Let y=f(x) be the solution of the differential equation ‌
dy
dx
+‌
xy
x2−1
=‌
x6+4x
√1−x2
−1
<x
<1
such that f(0)=0,
If 6‌
1∕2
∫
−1∕2
f(x)‌dx
=2π−α
, then α2 is equal to ____
[22 Jan 2025 Shift 2]
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