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JEE Main 22 Jan 2025 Shift 2 Paper

Section: Mathematics
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Question : 19 of 75
 
Marks: +1, -0
If x=f(y) is the solution of the differential equation (1+y2)+(x−2etan−1y)‌
dy
dx
=0,y∈(−‌
Ï€
2
,‌
Ï€
2
)‌‌ with f(0)=1, then f(‌
1
√3
) is equal to:

[22 Jan 2025 Shift 2]
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