Let E: \frac{x^2}{a^2}+\frac{y^2}{b^2}=1, a>b and H: \frac{x^2}{A^2}-\frac{y^2}{B^2}=1. Let the distance between the foci of E and the foci of H be 2 \sqrt{3}. If a-A=2, and the ratio of the eccentricities of E and H is \frac{1}{3}, then the sum of the lengths of their latus rectums is equal to : [22 Jan 2025 Shift 2]

JEE Main 22 Jan 2025 Shift 2 Paper

Section: Mathematics

Question : 16 of 75

Marks: +1, -0

Let E:‌

+‌

=1,a>b and H:‌

−‌

=1. Let the distance between the foci of E and the foci of H be 2√3. If a−A=2, and the ratio of the eccentricities of E and H is ‌

, then the sum of the lengths of their latus rectums is equal to :

[22 Jan 2025 Shift 2]

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