JEE Main 22 Jan 2025 Shift 1 Paper

Section: Mathematics

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Question : 13 of 75

Marks: +1, -0

Let x=x(y) be the solution of the differential equation y2‌dx+(x−‌

1

y

)dy=0. If x(1)=1, then x(‌

1

2

) is

[22 Jan 2025 Shift 1]

‌
3
2
+e
3−e
3+e
‌
1
2
+e

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