Let A= \{x:{| x^2-10 |} \leq 6\} and B=\{x:|x-2|>1\}. Then [21 Jan 2026 Shift 2]

Correct Answer is : B−A=(−∞,−4)∪(−2,1)∪(4,∞)

A \cup B=(-\infty, 1] \cup(2, \infty)

B-A=(-\infty,-4) \cup(-2,1) \cup(4, \infty)

JEE Main 21 Jan 2026 Shift 2 Paper Solved Paper

Section: Mathematics

Question : 9 of 75

Marks: +1, -0

Let A={x:|x2−10|≤6} and B={x:|x−2|>1}. Then

[21 Jan 2026 Shift 2]

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