The positive integer n, for which the solutions of the equation x(x+2)+(x+2)(x+4)+\cdots+(x+2 n-2)(x+2 n)=\frac{8 n}{3} are two consecutive even integers, is : [21 Jan 2026 Shift 2]

JEE Main 21 Jan 2026 Shift 2 Paper Solved Paper

Section: Mathematics

Question : 7 of 75

Marks: +1, -0

The positive integer n, for which the solutions of the equation x(x+2)+(x+2)(x+4)+⋯+(x+2n−2)(x+2n)=‌

are two consecutive even integers, is :

[21 Jan 2026 Shift 2]

Go to Question:

Prev Question

Next Question