JEE Main 21 Jan 2026 Shift 2 Paper Solved Paper

Section: Mathematics

Question : 5 of 75

Marks: +1, -0

Let z be the complex number satisfying |z−5|≤3 and having maximum positive principal argument.
Then 34|‌

5z−12

5iz+16

|2 is equal to:

[21 Jan 2026 Shift 2]

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