JEE Main 21 Jan 2026 Shift 2 Paper Solved Paper

Section: Mathematics
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Question : 23 of 75
 
Marks: +1, -0
If (‌
1
‌15C0
+‌
1
‌15C1
)
(‌
1
‌15C1
+‌
1
‌15C2
)
.
.
.(‌
1
‌15C12
+‌
1
‌15C13
)
=‌
α‌13
‌14C0‌14C1⋯‌14C12
, then 30α is equal to ____。
[21 Jan 2026 Shift 2]
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