JEE Main 21 Jan 2026 Shift 2 Paper Solved Paper
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Question : 13 of 75
Marks:
+1,
-0
Let y = y ( x ) be the solution of the differential equation s e c x
− 2 y = 2 + 3 s i n x , x ∈ ( −
,
) , y ( 0 ) = −
. Then y (
) is equal to :
[21 Jan 2026 Shift 2]
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