JEE Main 21 Jan 2026 Shift 1 Paper Solved Paper

Section: Mathematics

Question : 7 of 75

Marks: +1, -0

Let y=y(x) be the solution curve of the differential equation (1+x2)dy+(y−tan−1x)‌dx=0,y(0)=1. Then the value of y(1) is :

[21 Jan 2026 Shift 1]

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