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JEE Main 21 Jan 2026 Shift 1 Paper Solved Paper

Section: Mathematics
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Question : 20 of 75
 
Marks: +1, -0
Let f:R⟶(0,∞) be a twice differentiable function such that f(3)=18,f′(3)=0 and f′′(3)=4.
Then
lim
x⟶1
(loge(‌
f(2+x)
f(3)
)‌
18
(x−1)2
) is equal to :
[21 Jan 2026 Shift 1]
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