JEE Main 21 Jan 2026 Shift 1 Paper Solved Paper

Section: Mathematics
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Question : 2 of 75
 
Marks: +1, -0
If x2+x+1=0, then the value of (x+‌
1
x
)
4
+(x2+‌
1
x2
)
4
+(x3+‌
1
x3
)
4
+...
+(x25+‌
1
x25
)
4
is:
[21 Jan 2026 Shift 1]
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