Determine enthalpy of formation for H _2 O _2( l ), using listed enthalpies of reaction : N_2 H_4(l)+2 H_2 O_2(l) \rightarrow N_2(g)+4 H_2 O(l) ; ∆_{r} H_1^{\circ}=-818 kJ \/ mol N_2 H_4(l)+O_2(g) \rightarrow N_2(g)+2 H_2 O(l) ; ∆_{r} H_2^{\circ}=-622 kJ \/ mol H_2(g)+\frac{1}{2} O_2(g) \rightarrow H_2 O(l) ; ∆_{r} H_3^{\circ}=-285 kJ \/ mol

Correct Answer is : −187kJ∕mol

JEE Main 2026 Model Paper 1

Question : 31 of 75

Marks: +1, -0

Determine enthalpy of formation for H2O2(l), using listed enthalpies of reaction :
‌N2H4(l)+2H2O2(l)⟶N2(g)+4H2O(l);
‌∆rH1∘=−818kJ∕mol
‌N2H4(l)+O2(g)⟶N2(g)+2H2O(l);
‌∆rH2∘=−622kJ∕mol
‌H2(g)+‌

O2(g)⟶H2O(l);
‌∆rH3∘=−285kJ∕mol

−383kJ∕mol
−187kJ∕mol
−498kJ∕mol
None of these

Validate

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