If, for a positive integer n, the quadratic equation, x(x+1)+(x +1)(x+2)+..... +(x+\stackrel{––––––}{n-1})(x+n)=10n has two consecutive integral solutions, then n is equal to : [Main 2017]

JEE Main 2017 Solved Paper Solved Paper

Section: Mathematics

Question : 32 of 90

Marks: +1, -0

If, for a positive integer n, the quadratic equation, x(x+1)+(x+1)(x+2)+..... +(x+

––––––

n−1

)(x+n)=10n has two consecutive integral solutions, then n is equal to :

[Main 2017]

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