JEE Main 2017 Solved Paper Solved Paper

Section: Physics

Question : 14 of 90

Marks: +1, -0

A body of mass m=10–2kg is moving in a medium and experiences a frictional force F=−kv2. Its initial speed is v0=10ms–1. If, after 10 s, its energy is

mv02, the value of k will be:-

[Main 2017]

10−4kgm−1
10−1kgm−1s−1
10−3kgm−1
10−3kgs−1

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