JEE Main 2016 Question Paper

Section: Mathematics

Question : 33 of 90

Marks: +1, -0

Let P be the point on the parabola, y2=8x which is at a minimum distance from the centre C of the circle, x2+(y+6)2=1. Then the equation of the circle, passing through C and having its centre at P is:

[Main 2016]

x2+y2−x+4y−12=0
x2+y2−
x
4
+2y−24=0
x2+y2−4x+9y+18=0
x2+y2−4x+8y+12=0

Validate

Go to Question:

Prev Question

Next Question