JEE Main 2015 Question Paper

Section: Mathematics

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Question : 49 of 90

Marks: +1, -0

Let tan−1y=tan−1x+tan−1(

2x

1−x2

) where |x|<

1

√3

. Then a value of y is :

[Main 2015]

3x+x3
1−3x2
3x−x3
1+3x2
3x+x3
1+3x2
3x−x3
1−3x2

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