JEE Main 2015 Question Paper

Let the organic compound is R – Br
R−Br+AgNO3––––––––>AgBr↓
So number of moles of AgBr ≡ Number of moles of R – Br ≡ Number of moles of Br

141×10−3

188

= number of moles of Br=0.75×10−3
Mass of bromine =0.75×80×10−3g=60 mg
Percentage of bromine =

60

250

×100=24%