JEE Main 2013 Question Paper

Section: Physics

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Question : 78 of 90

Marks: +1, -0

A projectile is given an initial velocity of (

∧

i

+2

∧

j

),where

∧

i

is along the ground

∧

j

is along the vertical.If g=10m∕s2,the equation of its trajectory is:

[Main 2013]

y=2x−5x2
4y=2x−5x2
4y=2x−5x2
y=x−5x2

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