Consider : Statement − I : (p∧∼q) ∧ (∼p∧q) is a fallacy. Statement − II : (p\toq)\leftrightarrow(∼q\to∼p) is a tautology. [Main 2013]

Correct Answer is : Statement - I is True; Statement -II is true; Statement-II is not a correct explanation for Statement-I

Statement - I is True; Statement -II is true; Statement-II is not a correct explanation for Statement-I

Statement -I is True; Statement -II is False.

Statement -I is False; Statement -II is True

Statement -I is True; Statement -II is True; Statement-II is a correct explanation for Statement-I

JEE Main 2013 Question Paper

Section: Mathematics

Question : 42 of 90

Marks: +1, -0

Consider :
Statement − I : (p∧∼q)∧(∼p∧q) is a fallacy.
Statement − II :(p→q)↔(∼q→∼p) is a tautology.

[Main 2013]

Statement - I is True; Statement -II is true; Statement-II is not a correct explanation for Statement-I
Statement -I is True; Statement -II is False.
Statement -I is False; Statement -II is True
Statement -I is True; Statement -II is True; Statement-II is a correct explanation for Statement-I

p	q	~p	~q	p∧~q	~p^q	(p∧~q)^(~p∧q)
T	T	F	F	F	F	F
T	F	F	T	T	F	F
F	T	T	F	F	T	F
F	F	T	T	F	F	F

p	q	~p	~q	p⇒q	~q⇒~q	(p⇒q)⇔(~q⇒~p)
T	T	F	F	T	T	T
T	F	F	T	F	F	T
F	T	T	F	T	T	T
F	F	T	T	T	T	T

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