Given : A circle, 2x^2+2y^2=5 and a parabola, y^2 = 4\sqrt5x. Statement -I : An an equation of a common tangent to these curves is y=x+\sqrt5. Statement − II : If the line, y=mx+\sqrt5/m(m\neq0) is their common tangent, then m satisfies m^4-3m^2+2=0 [Main 2013]

Correct Answer is : Statement - I is True; Statement -II is true; Statement-II is not a correct explanation for Statement-I

Statement - I is True; Statement -II is true; Statement-II is not a correct explanation for Statement-I

Statement -I is True; Statement -II is False.

Statement -I is False; Statement -II is True

Statement -I is True; Statement -II is True; Statement-II is a correct explanation for Statement-I

JEE Main 2013 Question Paper

Section: Mathematics

Question : 33 of 90

Marks: +1, -0

Given : A circle, 2x2+2y2=5 and a parabola, y2=4√5x.
Statement -I: An an equation of a common tangent to these curves is y=x+√5.
Statement − II : If the line, y=mx+

√5

(m≠0) is their common tangent, then m satisfies m4−3m2+2=0

[Main 2013]

Statement - I is True; Statement -II is true; Statement-II is not a correct explanation for Statement-I
Statement -I is True; Statement -II is False.
Statement -I is False; Statement -II is True
Statement -I is True; Statement -II is True; Statement-II is a correct explanation for Statement-I

Validate

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