JEE Main 2013 Question Paper
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Question : 14 of 90
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Given E C r 3 + ∕ C r 0 = − 0.74 V ; E M n O 4 − ∕ M n 2 + 0 = 1.51 V
E C r 2 O 7 2 − ∕ C r 3 + 0 = 1.33 V ; E C l 2 ∕ C l − 0 = 1.36 V Based on the data given above, strongest oxidising agent will be:
[Main 2013]
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