JEE Main 20 July 2021 Shift 2 Solved Paper

Section: Physics

Question : 9 of 90

Marks: +1, -0

A particle is making simple harmonic motion along the X-axis. If at a distances x1 and x2 from the mean position the velocities of the particle are v1 and v2 respectively. The time period of its oscillation is given as:

[20 Jul 2021 Shift 2]

T=2π√
x22+x12
v12−v22
T=2π√
x22+x12
v12+v22
T=2π√
x22−x12
v12+v22
T=2π√
x22−x12
v12−v22

Validate

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